(2x^2+11x+12)/x+k=2x+3

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Solution for (2x^2+11x+12)/x+k=2x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^2+11*x+12)/x+k = 2*x+3 // - 2*x+3

(2*x^2+11*x+12)/x+k-(2*x)-3 = 0

(2*x^2+11*x+12)/x+k-2*x-3 = 0

(2*x^2+11*x+12)/x+(k*x)/x+(-2*x*x)/x+(-3*x)/x = 0

k*x+2*x^2-2*x*x+11*x-3*x+12 = 0

k*x+2*x^2-2*x^2+11*x-3*x+12 = 0

k*x+11*x-3*x+12 = 0

k*x+8*x+12 = 0

k*x+8*x+12 = 0

8*x+12 = 0 // - 12

8*x = -12 // : 8

x = -12/8

x = -3/2

x+3/2 = 0

(x+3/2)/x = 0

(x+3/2)/x = 0 // * x

x+3/2 = 0

x+3/2 = 0 // - 3/2

x = -3/2

x = -3/2

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